I have graphed the curve and the derivative will leads to plus zero (+0) when x --> infinity. The derivative of the function \ (\frac {1} {x^n}) can be simplified by rewriting it as \ (x^ {-n}). We know the derivative would be the denominator times the derivative of the numerator (which would be zero in this case), minus the numerator times the derivative of the denominator.
Another participant clarifies that the derivative of ln (x) is 1/x, applicable only for x > 0, and similarly for ln (-x) when x < 0, indicating that the absolute value is indeed relevant for integration. Homework Help Overview The discussion revolves around finding the derivative of the function 1/x, a common topic in calculus. The discussion revolves around the representation of the derivative as a matrix, particularly in the context of polynomials and potentially more general functions.
The discussion centers around the question of why the derivative of the function e^x is equal to e^x itself. So in the domain of 0<x<inf, the derivative must be positive.
Derivative of 1/lnx - Physics Forums.
Is the Derivative of (1+1/x)^x Always Positive?
Want to understand how to express the derivative as a matrix.
- Why is the Derivative of e^x e^x?
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Sources
- https://www.physicsforums.com/threads/derivative-of-1-x-n-simplifying-the-process.128646/
- https://www.physicsforums.com/threads/derivative-of-1-lnx.194571/
- https://www.physicsforums.com/threads/do-you-need-absolute-value-around-argument-for-log-and-ln.1024137/
- https://www.physicsforums.com/threads/derivative-of-1-x-solving-a-common-calculus-problem.211489/
